Several_Way_To_OpenFileDialog

发表于

OpenDialog

Way 01 使用win32控件OpenFileDialog

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Microsoft.Win32.OpenFileDialog ofd = new Microsoft.Win32.OpenFileDialog();
            ofd.DefaultExt = ".xml";
            ofd.Filter = "xml file|*.xml";
            if (ofd.ShowDialog() == true)
            {
                Console.WriteLine("if");
            }

类似的还有 Microsoft.Win32.SaveFileDialog

Way 02 使用Forms中的OpenFileDialog控件 or FolderBrowserDialog

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System.Windows.Forms.OpenFileDialog openFileDialog1 = new System.Windows.Forms.OpenFileDialog();
            openFileDialog1.InitialDirectory = "c:\\";
            openFileDialog1.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*";
            openFileDialog1.FilterIndex = 2;
            openFileDialog1.RestoreDirectory = true;
            if (openFileDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)
            {
                //此处做你想做的事 ...=openFileDialog1.FileName; 
                Console.WriteLine(openFileDialog1.FileName);
            }



//File
FolderBrowserDialog folderBrowserDialog = new FolderBrowserDialog();
            folderBrowserDialog.Description = "Please select Data Folder";
            if (folderBrowserDialog.ShowDialog() == DialogResult.OK)
            {
                Console.WriteLine("WCNBB");
            }

Way 03 使用win32 api

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BOOL WINAPI GetOpenFileName(  __inout  LPOPENFILENAME lpofn)

Way 04 使用Windows API Code Pack

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var dialog = new CommonOpenFileDialog();
dialog.IsFolderPicker = true;
CommonFileDialogResult result = dialog.ShowDialog();